40 lines
1.6 KiB
Python
40 lines
1.6 KiB
Python
""" upload one directory from the current working directory to aws """
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from pathlib import Path
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import os
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import glob
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import boto3
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def upload_dir(local_dir, aws_init_dir, bucket_name, tag, prefix='/'):
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"""
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from current working directory, upload a 'localDir' with all its subcontents (files and subdirectories...)
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to a aws bucket
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Parameters
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----------
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local_dir : localDirectory to be uploaded, with respect to current working directory
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aws_init_dir : prefix 'directory' in aws
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bucket_name : bucket in aws
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tag : tag to select files, like *png
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NOTE: if you use tag it must be given like --tag '*txt', in some quotation marks... for argparse
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prefix : to remove initial '/' from file names
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Returns
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-------
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None
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"""
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s3 = boto3.resource('s3')
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cwd = str(Path.cwd())
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p = Path(os.path.join(Path.cwd(), local_dir))
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mydirs = list(p.glob('**'))
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for mydir in mydirs:
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file_names = glob.glob(os.path.join(mydir, tag))
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file_names = [f for f in file_names if not Path(f).is_dir()]
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rows = len(file_names)
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for i, file_name in enumerate(file_names):
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# file_name = str(file_name).replace(cwd, '')
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s3_file_name = ""
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if file_name.startswith(prefix): # only modify the text if it starts with the prefix
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s3_file_name = file_name.replace(prefix, "", 1) # remove one instance of prefix
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print(f"fileName {file_name}")
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if len(s3_file_name) > 0:
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s3_path = os.path.join(aws_init_dir, str(s3_file_name))
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s3.meta.client.upload_file(file_name, bucket_name, s3_path) |